Topic: What are the odds??? | |
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I had a quasi creepy situation happen too but not quite as specific. In one year, all the guys I met, that I became interested in dating, were all Virgos. That didn't dictate whether I would date them or not -- but it was weird. I'd say over-look it and see if he is worthy of you. Coincidence is a goofy thing ... You're brave, I can NOT handle Virgos My best friend is a Virgo. I love him to death but he is a pain! I don't do well romantically with Virgos, but again, I try not to let that dictate who I date. Patterns are just that -- patterns; however, not enough for me to put the de-flecto shield up again all Virgos! |
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I am reporting this thread for being offensive shut up Dan.
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well, I found this... Here's a fun and easy application of probability to show the odds are good that at least two people in a relatively small group will share the same birthday. Let's say you asked me when I celebrated my birthday, and I replied, "guess." If you were nice enough to play along, you would very probably guess wrong. Ignoring leap years, there are 365 days in a year, and I only celebrate my birthday on one of those days. The odds of you correctly guessing my birthday is 1 in 365 (or .003%). That's an easy concept to grasp. It makes sense that you're not likely to guess my birthday. Now let's say you know my birthday. What are the odds that the next person you meet on the street will share the same birthday as me? Again, the odds are abysmal: 1 out of 365. Therefore it seems very unlikely you'll find two people who share the same birthday, right? Well, not necessarily. Let's say you know a group of 10 people. What are the odds that two of them share the same birthday? Without doing any math, it just seems the odds are low. How about 20 people? Or 30 people? Are the odds of two people sharing a birthday really low? How large does a group have to be until it actually becomes likely that two people actually DO share a birthday? The answer may surprise you. But before we calculate it, let's predict something easier: dice. You pick up two fair dice, give them a shake, and roll. What are the odds of rolling a match? (That's sort of like two people sharing a birthday.) One strategy is to first calculate the odds of NOT rolling a match and then subtract from 1. That provides the odds of the opposite event (ie, rolling a match). Think of flipping a coin. The odds of it landing heads are 1/2. Therefore the odds of it NOT landing heads are 1/2. Same principle applies here. Let's do it: First calculate all the possible combinations of two rolled dice: 11 12 13 14 15 16 21 22 23 24 25 26 31 32 33 34 35 36 41 42 43 44 45 46 51 52 53 54 55 56 61 62 63 64 65 66 Count the combinations and you get 36. We could have achieved the same result by multiplying 6 x 6. So there are 36 possibilities. How many of those possibilities do NOT provide a match? xx 12 13 14 15 16 21 xx 23 24 25 26 31 32 xx 34 35 36 41 42 43 xx 45 46 51 52 53 54 xx 56 61 62 63 64 65 xx Count the possibilities and you get 30. Again we could have achieved the same result by multiplying 6 x 5. The first die has 6 ways it can land. The second die only has 5 ways to land if it is to satisfy the condition of NOT matching. Therefore there are 6 x 5 combinations of dice not matching. So the odds of rolling two dice that do NOT match is 30/36, or 5/6. The odds of rolling the opposite situations -- two dice that DO match -- are consequently 1 - 5/6, or 1/6. It would have been easier to just count the number of matches in our table, but the mathematical method will come in handy when calculating the odds of two people in a group having the same birthday. Speaking of which, let's do that now. Pretend we have a slightly overcrowded classroom of 30 students. What are the odds of any two of the kids having the same birthday? As we did with the dice, let us first count the possible combinations, except minus the table. The total combinations of dice rolls was 6 x 6. Likewise, the total combination of birthdays is 365 x 365 x 365 x....(30 times), or more succinctly 36530. (Again we ignore leap years.) That's our denominator. Without calculating we can quickly see that's a huge number. Now, as before, let's calculate the number of possibilities that do NOT provide a matching birthday. The first person states his birthday. For the next person to NOT have the same birthday, she has to pick from 364 days. The next person must choose from 363 days. And so on. Again were trying to calculate the number of combinations in which no one has a matching birthday. For the dice, the calculation was 6 x 5. Here we do the same thing: 365 x 364 x 363 x 362 x ... x 339 x 338 x 337 x 336 We can write this more concisely as follows: where n equals the number of kids in the classroom (in this case 30) and the exclamation point means "factorial". Factorials are defined as n*(n-1)*(n-2)....(3)(2)(1). For example, 6! = 6*5*4*3*2*1. Calculate and you have our numerator. Put the two together to find the odds of NOT finding at least two kids with the same birthday in a group of 30 kids: There's about a 30% chance that you will NOT find at least two kids who share the same birthday in a group of 30. Therefore the opposite situation, that you WILL find at least two kids with the same birthday in a group of 30, is a whopping 70% (1 - .3 = .7). In fact, we find that in a group of 23 kids, your odds are better than 50% to find at least two people with the same birthday. And that's the Birthday Paradox. It doesn't seem possible that the odds should be so good to find at least two people with the same birthday in such a relatively small group. But they are. Remember, these are not the odds of finding someone with the same birthday as YOU in a group of 30 people. These are the odds of finding at least two people out of 30 who share a birthday. SHUT UP DAN! My head hurts Shut up, Dan! |
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I wonder if theres like a numerology website that could give you some more interesting or spooky facts about those days, and stuff.. Maybe here: http://www.aboutnumerology.com/ |
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I am reporting this thread for being offensive shut up Dan. shut up dan |
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There's a numerology lady around here who thinks numbers and how they line up (or some crap like that) plays into things. Maybe ask her.
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'(or some crap like that)' was the vital part of that post, Connie!! haha
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'(or some crap like that)' was the vital part of that post, Connie!! haha Yes. But I thought it would help. Sure seemed to set'm straight for dying out of order! |
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You forgot to say, "Shut up, Dan".
It's okay, I'll do it for you. "Shut up, Dan." Shut up, Dan. |
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Ok...where is this lady? I need here NOW. lol
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You forgot to say, "Shut up, Dan". It's okay, I'll do it for you. "Shut up, Dan." Shut up, Dan. No I said it on his own shut up thread! |
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Ok...where is this lady? I need here NOW. lol Really! You don't. Trust us! |
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Oops! My bad, I haven't seen that thread yet.
Shut up, Dan. |
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I was born on 3rd April 1976
1 + 9 + 7 +6=23 i was 23 on 3rd April 1999 WOW! Imagine that. |
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Maybe i should make a F**k Off, Keith thread!
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Ok...where is this lady? I need here NOW. lol Really! You don't. Trust us! Damn..that bad, huh? Shut up, Dan F*ck off, Keith |
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Well, 9 months and 2 weeks earlier is the Fourth of July. Probably lots of people born right around Mid-April..... My son was concieved on July 4th 2006, born March 25 2007. |
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Maybe i should make a F**k Off, Keith thread! |
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Maybe i should make a F**k Off, Keith thread! Wrong Keith..oldie Keith |
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Ok...where is this lady? I need here NOW. lol Really! You don't. Trust us! Connie SHHHHHHHHHHHHHH!!! What we're you thinking??? |
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