Do you think about why the mobile memory cards are not made of 3GB,5GB,7GB...
There is a reason behind it. Any body khow about this give your view,
After this i'll give answer.

no yar m nt think about it...

plz tell ans

I have no idea... What?

I have no idea... What?

because data storage in computer is done with help of binary (0,1) number system. thats why the storage capacity are made with the power of 2 that is 2GB, 4GB, 8GB , 16GB and so on.

Thank you friendeepu.

It is not a stick reason, that binary number capsity. what's relation between binary number (0,1) and 2gb 4gb 8gb and so on? I give its acurate ans.

Friendeepu- It is not a stick reason, that binary number capsity. what's relation between binary number (0,1) and 2gb 4gb 8gb and so on? I give its acurate ans.

Friendeepu- It is not a stick reason, that binary number capsity. what's relation between binary number (0,1) and 2gb 4gb 8gb and so on? I'll give its acurate ans.

actually pc=macs cant read odd sets right. .. The Amiga can. To wit the Amiga has odd ram sets of 3 megs and so forth . Its the outdated arcane x86 mindset which is the problem.

Because making 1gb, 3gb, 5gb ... There is very diffculity since,
1GB flash drives do exist, and 1TB will probably be in the future.
To get other odd number capacities would mean manufacturers using extra chips. Why make a drive for example with 2 x 4GB chips a 1GB chip to make a 9GB drive?
7GB would be worse. You'd need a 4GB 2GB 1GB! Why go to the trouble and expense when 1x8GB or 2x4GB would most likely be cheaper to manufacture?

8 bits = 1 byte
1024 bytes = 1 kilobyte
1024 kilobytes(KB) = 1 megabyte(MB)
1024 megabytes(MB) = 1 gigabyte(GB)
1024 gigabytes(GB) = 1 terabyte(TB).

Thank you friends. We wish you that you have a great nice day daily.

Wrong again SheshNath44.
They make odd chips in fact when a pc formats the chip it doesnt see all the chip it only sees maybe 95% of it.Amiga Sees all so when an Amiga formats a chip or thumb-drive u have 100% available so a 32gig is actually seen as 33 gig on an Amiga. PC=MAc in the architecture that is made they never see the full bits case in point . Which is why u loose a full hard drive when formatted. Which is why Amiga people like me always laughed when we had a 545 gig hard drive out of a 540 gig and u guys only saw 530 .

Same with ram. You have to have the exact model of ram and the exact speed to match .you cant have the slow speed in front of the fast one. The Amiga doesnt care .The Amiga dynamic addresses the speed in true real-time. No waite states .You have waite states. The pc motherboard isnt mulitasking or real-time u need both to do either of these.

Read with carefuly Hp20111'.IT now going to deep.
A controllers have a certain bit width. Typically, they require a 16-bit path to flash memory. Flash chipstypically provide a 4 bit path. So that means your choices are 4 chips (one bank) or 8 (two banks).
Each flash chip has a certain number of inputs. Each input can be in two possiblestates, and that selects a single 4-bit location. If the chip has 32 inputs, that will mean it has 2^32 (4 billion) possible combinations of those inputs. If the manufacturer chooses to use 4 such chips, that means each of the 4 billion possible combinations can store 4*4 bits or 2 bytes. That will make an 8GB memory card or flash drive.
Now, what can the manufacturer do? For the number of chips, he can't use 5 or 3 because that won't produce the 16-bit locations the controller needs. So he can go to 8 chips, giving him 16GB. Or he could use one chip and a 4-bit controller to get 4GB.
He could switch to a chip with 31 inputs instead of 32. That will give him a 4GBflash drive again. He can pick 8 chips with 33 inputs. That gives him 32GB.
If you look at the math, no combination of options would give him 3GB or 5GB or any.The controller needs to assemble data into bytes and the chips need to use address lines to select.
You could, in theory, make, say, a 5GB flash drive, you'd need to use 5 banks of 1GB each. But having 5 banks would force uncomfortable tradeoffs.
For each bank to be 16-bits using 4-bit chips, you'd need 4 chips for each bank, or 20 flash chips. That's going to be bulky, waste power, and mean increased wiring and an increased failure rate. It will also increased costs.
You can make an 8GB stick (with a single 8GB bank) much more cheaply than such a 5-bank, 5GB stick.
It's how the data is stored in the memory cells and related to "two to the power of n", 2^n (binary number). That is how data is stored and that is how nature works too. For example, 2^0 = 1, 2^1 = 2, 2^2 = 4, 2^3=8, 2^4=16, etc..2^n, that's why there is no odd number.
I think yo understood,
Thank you.

Read with carefuly Hp20111'.IT now going to deep.
A controllers have a certain bit width. Typically, they require a 16-bit path to flash memory. Flash chipstypically provide a 4 bit path. So that means your choices are 4 chips (one bank) or 8 (two banks).
Each flash chip has a certain number of inputs. Each input can be in two possiblestates, and that selects a single 4-bit location. If the chip has 32 inputs, that will mean it has 2^32 (4 billion) possible combinations of those inputs. If the manufacturer chooses to use 4 such chips, that means each of the 4 billion possible combinations can store 4*4 bits or 2 bytes. That will make an 8GB memory card or flash drive.
Now, what can the manufacturer do? For the number of chips, he can't use 5 or 3 because that won't produce the 16-bit locations the controller needs. So he can go to 8 chips, giving him 16GB. Or he could use one chip and a 4-bit controller to get 4GB.
He could switch to a chip with 31 inputs instead of 32. That will give him a 4GBflash drive again. He can pick 8 chips with 33 inputs. That gives him 32GB.
If you look at the math, no combination of options would give him 3GB or 5GB or any.The controller needs to assemble data into bytes and the chips need to use address lines to select.
You could, in theory, make, say, a 5GB flash drive, you'd need to use 5 banks of 1GB each. But having 5 banks would force uncomfortable tradeoffs.
For each bank to be 16-bits using 4-bit chips, you'd need 4 chips for each bank, or 20 flash chips. That's going to be bulky, waste power, and mean increased wiring and an increased failure rate. It will also increased costs.
You can make an 8GB stick (with a single 8GB bank) much more cheaply than such a 5-bank, 5GB stick.
It's how the data is stored in the memory cells and related to "two to the power of n", 2^n (binary number). That is how data is stored and that is how nature works too. For example, 2^0 = 1, 2^1 = 2, 2^2 = 4, 2^3=8, 2^4=16, etc..2^n, that's why there is no odd number.
I think yo understood,
Thank you.

SheshNath44:

Posting twice doesn't make it right - especially when it comes from wiki lol rofl. Just shows your sign of insecurity. Plus, it took u this long to look it up and respond- Pathetic.

You never had an Amiga. You dont know how ram/hard drives are made. You just see the Paper specs. Just like saying a car will get 35 mpg -- yeah on a best day . When it actually gets 30-33.
I have a Degree in Computer Electrical Engineering
YOu DOnt.
I have an Amiga. You dont and consistently I use any thumb-drive its always more then it says as with hard drive.SO get a real system. Get an Amiga. ITs the x86 design It cant see the total amount of space. Really are you that FOOLish to think that every space is cut off at exact point . NO they always leave extra space. In case of errors. Case in point the celeron chip was just a cpu that was a chip with a messed up coprocessor. SO they sold it as such to make money from the quagmire.

HERE ENDTH THE LESSON